Java Program to check if year is a LEAP year or Not

In this program we will write a Java program to check whether a year is a leap year or not. A leap year is a special year which has 1 day extra. This normal years have 365 days, however a leap year has 366 days. A leap year comes every 4 years. Here is the logic to find whether a year is a leap year or not.

The rule states:

“Every year that is exactly divisible by four is a leap year, except for years that are exactly divisible by 100, but these centurial years are leap years if they are exactly divisible by 400.”

For example,
if year = 2400, it is leap year,(Condition 1 satisfied)
but if year = 2200, is NOT a leap year, (Cond. 2 not satisfied),
and if year = 2020, is a leap year, (Cond. 2 satisfied).

To check whether a year is a leap year or not, you need to check the following 3 conditions:

IF
1. Any year that is divisible by 400 is definitely a leap year.

ELSE IF
2. If divisible by 4 AND not divisible by 100 then a leap year.

ELSE
not a leap year.

public class JavaApplication4 {

    public static void main(String[] args) {
     
        int year = 2020;
        
        if(year%400==0)
        {
            System.out.println("Leap Year");
        }
        else if(year%4==0 && year%100!=0)
        {
            System.out.println("Leap Year");
        }
        else
        {
            System.out.println("Not a Leap Year");
        }
      
    }
}

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